Adebayo A. Adeniyi
a.aadeniyi@yahoo.com
Please, I am trying to get the total energy, enthalpy, gibbs free energy of my system. I compute the thermochemical properties of simple molecule "H2O" but I am confused because I obtained two thermochemical output as follows:
THERMOCHEMISTRY AT T= 298.15 K
-------------------------------
USING IDEAL GAS, RIGID ROTOR, HARMONIC NORMAL MODE APPROXIMATIONS.
P= 1.01325E+05 PASCAL.
ALL FREQUENCIES ARE SCALED BY 1.00000
THE MOMENTS OF INERTIA ARE (IN AMU*BOHR**2)
2.07890 4.38535 6.46425
THE ROTATIONAL SYMMETRY NUMBER IS 1.0
THE ROTATIONAL CONSTANTS ARE (IN GHZ)
867.32830 411.16213 278.93251
THE HARMONIC ZERO POINT ENERGY IS (SCALED BY 1.000)
0.021773 HARTREE/MOLECULE 4778.512983 CM**-1/MOLECULE
13.662468 KCAL/MOL 57.163766 KJ/MOL
Q LN Q
ELEC. 1.00000E+00 0.000000
TRANS. 3.00431E+06 14.915558
ROT. 8.68998E+01 4.464756
VIB. 1.00017E+00 0.000170
TOT. 2.61118E+08 19.380484
E H G CV CP S
KJ/MOL KJ/MOL KJ/MOL J/MOL-K J/MOL-K J/MOL-K
ELEC. 0.000 0.000 0.000 0.000 0.000 0.000
TRANS. 3.718 6.197 -36.975 12.472 20.786 144.800
ROT. 3.718 3.718 -11.068 12.472 12.472 49.593
VIB. 57.167 57.167 57.163 0.106 0.106 0.014
TOTAL 64.604 67.083 9.121 25.050 33.364 194.407
E H G CV CP S
KCAL/MOL KCAL/MOL KCAL/MOL CAL/MOL-K CAL/MOL-K CAL/MOL-K
ELEC. 0.000 0.000 0.000 0.000 0.000 0.000
TRANS. 0.889 1.481 -8.837 2.981 4.968 34.608
ROT. 0.889 0.889 -2.645 2.981 2.981 11.853
VIB. 13.663 13.663 13.662 0.025 0.025 0.003
TOTAL 15.441 16.033 2.180 5.987 7.974 46.464
......END OF NORMAL COORDINATE ANALYSIS......
How do I get the total E, H, G ? I suppose the E should be the FINAL ENERGY which is -75.5859597519 in the output file. What does "Q" and "LN Q" stands for ?
Thanks.