I faced a problem. I successfully got CASSCF(11,11) solution with two doublets and one quartet. I use SA-MCSCF for these states since they are sit very close to each other. The total number of states is 10. I did calculations without $MCSCF iforb=.t. sd=.t. $END. Then i added this keyword and reused optimized orbitals, but my solution was quite different. The state order before was D,D,Q, but with iforb=.t. it is Q,7... Is it normal effect of iforb or there is a pitfall somewhere here?
My input file looks
$CONTRL SCFTYP=mcscf RUNTYP=energy d5=.t. icharg=0 wide=.t. gencon=.t.
MAXIT=50 icut=12 itol=35 exetyp=run inttyp=hondo mult=2 $END
$det ncore=150 nact=11 nels=11 wstate(1)=1,1,1,-0 nstate=10
pures=.f. cvgtol=1d- $end
$mcscf cistep=aldet fors=.t. ntrack=5 numfo=5 iforb=1 canonc=1 sd=.t. $end
$TRANS DIRTRF=.t. mode=112 mptran=2 AOINTS=DIST altpar=.t. cuttrf=1d-13 $END
$SYSTEM MWORDS=250 nojac=1 mxbcst=-1 $END
$MPI mxgsum=0x40000 mnpdot=1d9 $end
$BASIS extfil=.t. $END
$p2p p2p=.t. dlb=.t. $end
$smp httfix(1)=.t. $end
$moorth nostf=1 nozero=1 syms=1 symden=1 symvec=1 tole=0 tolz=0 $end
$guess guess=moread norb=708 $end
I also tried to read orbitals with asis=.t. but it didn't help.