Pedro Silva
pedros@ufp.pt
As expected, the lowest energy corresponds to the triplet state with two singly-occupied p orbitals. The following results are strange: I would only expect differences between the RHF and UHF MULT=1 results to arise when a bond is getting too stretched, not in a single-atom system like this one. I get the same RHF energy when I try to use the $VEC group from the UHF MULT=1 as guess. Applying the Ovchinnikov an Labanowski correction to the spin-contaminated UHF MULT=1 energy still leaves a pure singlet energy far below that computed by RHF.
I'm sorry if this comes across as a very silly question, but does any one know the reason for this differences?
Pedro